On 21.11.2010 15:18, Robert Haas wrote:
> On Sat, Nov 20, 2010 at 4:07 PM, Tom Lane<tgl@sss.pgh.pa.us> wrote:
>> Robert Haas<robertmhaas@gmail.com> writes:
>>> So what DO we need to guard against here?
>>
>> I think the general problem can be stated as "process A changes two or
>> more values in shared memory in a fairly short span of time, and process
>> B, which is concurrently examining the same variables, sees those
>> changes occur in a different order than A thought it made them in".
>>
>> In practice we do not need to worry about changes made with a kernel
>> call in between, as any sort of context swap will cause the kernel to
>> force cache synchronization.
>>
>> Also, the intention is that the locking primitives will take care of
>> this for any shared structures that are protected by a lock. (There
>> were some comments upthread suggesting maybe our lock code is not
>> bulletproof; but if so that's something to fix in the lock code, not
>> a logic error in code using the locks.)
>>
>> So what this boils down to is being an issue for shared data structures
>> that we access without using locks. As, for example, the latch
>> structures.
>
> So is the problem case a race involving owning/disowning a latch vs.
> setting that same latch?
No. (or maybe that as well, but that's not what we've been concerned
about here). As far as I've understood correctly, the problem is that
process A does something like this:
/* set a shared variable */
((volatile bool *) shmem)->variable = true;
/* Wake up process B to notice that we changed the variable */
SetLatch();
And process B does this:
for (;;)
{ ResetLatch(); if (((volatile bool *) shmem)->variable) DoStuff();
WaitLatch();
}
This is the documented usage pattern of latches. The problem arises if
process A runs just before ResetLatch, but the effect of setting the
shared variable doesn't become visible until after the if-test in
process B. Process B will clear the is_set flag in ResetLatch(), but it
will not DoStuff(), so it in effect misses the wakeup from process A and
goes back to sleep even though it would have work to do.
This situation doesn't arise in the current use of latches, because the
shared state comparable to shmem->variable in the above example is
protected by a spinlock. But it might become an issue in some future use
case.
-- Heikki Linnakangas EnterpriseDB http://www.enterprisedb.com