Re: grouping subsets

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От Rainer Stengele
Тема Re: grouping subsets
Дата
Msg-id 4C4846CE.4070701@diplan.de
обсуждение исходный текст
Ответ на Re: grouping subsets  ("Oliveiros d'Azevedo Cristina" <oliveiros.cristina@marktest.pt>)
Список pgsql-sql
Hi Oliveiros,

yes, the date is always incremented - but anyway the date column is not really the point!
Actually the first tow columns are relevant.
I want them gouped together as indicated, adding up column 1 in the blocks with identical second column, but not adding
upover all the rows.
 

Hope I could express it!

Mit freundlichen Grüßen / Best Regards   Rainer Stengele 

__|___  | Dipl. Inf. (Univ.) Rainer Stengele    | Technical Control - System Administration   | | email    :
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                      | Wetterkreuz 27 | 91058 Erlangen, Germany                      
 
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Am 22.07.2010 15:18, schrieb Oliveiros d'Azevedo Cristina:
> Howdy, Rainer.
>
> Please advice me,
>
> The dates always follow that sequential pattern?
>
> Or can be holes on the dates sequence?
>
> Best,
> Oliveiros
>
> ----- Original Message ----- From: "Rainer Stengele" <rainer.stengele@diplan.de>
> To: <pgsql-sql@postgresql.org>
> Sent: Thursday, July 22, 2010 9:09 AM
> Subject: [SQL] grouping subsets
>
>
>> Hi,
>>
>> having a table similar to
>>
>> | 1 | B | [2010-07-15 Do] |
>> | 1 | B | [2010-07-16 Fr] |
>> |---+---+-----------------|
>> | 2 | C | [2010-07-17 Sa] |
>> | 2 | C | [2010-07-18 So] |
>> |---+---+-----------------|
>> | 1 | B | [2010-07-19 Mo] |
>> | 1 | B | [2010-07-20 Di] |
>> | 1 | B | [2010-07-21 Mi] |
>> | 1 | B | [2010-07-22 Do] |
>> |---+---+-----------------|
>> | 3 | D | [2010-07-23 Fr] |
>>
>> a simple group by gives me:
>>
>> | 6 | B |
>> | 4 | C |
>> | 3 | D |
>>
>>
>> What I want to get is the values grouped by "subset", where a subset is a set of rows with identical column until
thecolum changes.
 
>> Is there a way to get
>>
>> | 2 | B |
>> | 4 | C |
>> | 4 | B |
>> | 3 | D |
>>
>> by SQL only?
>>
>> - Rainer
>>
>>
>>
>>
>>
>> -- 
>> Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org)
>> To make changes to your subscription:
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>
>


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