A DISTINCT problem removing duplicates

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От Richard Huxton
Тема A DISTINCT problem removing duplicates
Дата
Msg-id 493E3E5F.6090304@archonet.com
обсуждение исходный текст
Ответы Re: A DISTINCT problem removing duplicates  (Tom Lane <tgl@sss.pgh.pa.us>)
Список pgsql-sql
The scenario is - a list of documents, some of which may be (near)
duplicates of others, one document being in many duplicate-sets and a
duplicate-set containing many documents.

We want to see a list with only one document (any one) from each
duplicate set. There's an example script attached.

So:

documents  (docid SERIAL, title text, PRIMARY KEY (docid));
duplicates (docid int REFERENCES documents, dup_set SERIAL,
            PRIMARY KEY (docid, dup_set));

This allows one document to be part of multiple duplicate sets, but
that's fine - this is a "fuzzy" match. If two documents match and one of
them is already in the duplicates table then I add the second with the
same dup_set value. If neither are present, generate a new set number.
Match documents in a well-defined order and it's all nice and simple.

A self-join on the duplicates table gives me a count of how many
duplicates each document has. A left-join from the documents table can
list documents and if/how many duplicates they have. The problem comes
when I don't want to see duplicates:

SELECT DISTINCT ON (dup_set)
    ds.dup_set, d.docid, d.title, COALESCE(ds.num_dups, 0) AS num_dups
FROM
    documents d
LEFT JOIN
    (
        SELECT dup1.docid, dup1.dup_set, count(*) - 1 AS num_dups
        FROM duplicates dup1
        JOIN duplicates dup2 USING (dup_set)
        GROUP BY dup1.docid, dup1.dup_set
    ) ds
USING (docid)
ORDER BY dup_set, docid
;

Documents without duplicates have a NULL dup_set. The DISTINCT ON
considers two nulls to be equal, which means we only ever see one
unduplicated document.

I've got two work-arounds. The first is to create a separate sequence
that doesn't overlap with dup_set's values and use that:

CREATE SEQUENCE not_duplicate_seq MINVALUE -999999 MAXVALUE -1 CYCLE;

SELECT DISTINCT ON (dup_set)
    COALESCE(dup_set, nextval('not_duplicate_seq')) AS dup_set,
    d.docid, d.title, COALESCE(ds.num_dups, 0) AS num_dups
...

That works, but is arguably a bit too "clever" if you know what I mean.

The other alternative is to separate duplicated and non-duplicated
documents and UNION them. That's simple enough to see what's happening
but does seem ugly.

Anyone got anything more elegant? I'm happy to alter the duplicates
table so long as it doesn't make it complicated to update.

--
  Richard Huxton
  Archonet Ltd
BEGIN;

CREATE SCHEMA duptest;

SET search_path = duptest;

CREATE TABLE documents (
    docid SERIAL NOT NULL,
    title text,
    PRIMARY KEY (docid)
);

CREATE TABLE duplicates (
    docid   int NOT NULL REFERENCES documents ON DELETE CASCADE,
    dup_set SERIAL NOT NULL,
    PRIMARY KEY (docid, dup_set)
);

-- Five documents
INSERT INTO documents (docid, title)
SELECT i, 'document number ' || i FROM generate_series(1, 6) i;

-- duplicates are (1,3) and (2,4) - 5,6 are not
INSERT INTO duplicates (docid, dup_set)
SELECT i, (i % 2)+1 FROM generate_series(1, 4) i;

SELECT setval('documents_docid_seq', (SELECT max(docid)+1 FROM documents));
SELECT setval('duplicates_dup_set_seq', (SELECT max(dup_set)+1 FROM duplicates));

-- This is a list of all documents with how many duplicates they have
SELECT dup_set, d.docid, d.title, COALESCE(ds.num_dups, 0) AS num_dups
FROM
    documents d
LEFT JOIN
    (
        SELECT dup1.docid, dup1.dup_set, count(*) - 1 AS num_dups
        FROM duplicates dup1
        JOIN duplicates dup2 USING (dup_set)
        GROUP BY dup1.docid, dup1.dup_set
    ) ds
USING (docid)
ORDER BY dup_set, docid
;

-- This DOESN'T work because nulls are considered equal by DISTINCT ON
SELECT DISTINCT ON (dup_set)
    dup_set, d.docid, d.title, COALESCE(ds.num_dups, 0) AS num_dups
FROM
    documents d
LEFT JOIN
    (
        SELECT dup1.docid, dup1.dup_set, count(*) - 1 AS num_dups
        FROM duplicates dup1
        JOIN duplicates dup2 USING (dup_set)
        GROUP BY dup1.docid, dup1.dup_set
    ) ds
USING (docid)
ORDER BY dup_set, docid
;

-- Work around is to fake a unique id for non-duplicates
CREATE SEQUENCE not_duplicate_seq MINVALUE -999999 MAXVALUE -1 CYCLE;

SELECT DISTINCT ON (dup_set)
    COALESCE(dup_set, nextval('not_duplicate_seq')) AS dup_set,
    d.docid, d.title, COALESCE(ds.num_dups, 0) AS num_dups
FROM
    documents d
LEFT JOIN
    (
        SELECT dup1.docid, dup1.dup_set, count(*) - 1 AS num_dups
        FROM duplicates dup1
        JOIN duplicates dup2 USING (dup_set)
        GROUP BY dup1.docid, dup1.dup_set
    ) ds
USING (docid)
ORDER BY dup_set, docid
;

-- Second alternative - UNION duplicated and non-duplicated documents
SELECT DISTINCT ON (dup_set)
    ds.dup_set, d.docid, d.title, num_dups
FROM
    documents d
LEFT JOIN
    (
        SELECT dup1.docid, dup1.dup_set, count(*) - 1 AS num_dups
        FROM duplicates dup1
        JOIN duplicates dup2 USING (dup_set)
        GROUP BY dup1.docid, dup1.dup_set
    ) ds
USING (docid)
WHERE num_dups > 0
UNION ALL
SELECT
    ds.dup_set, d.docid, d.title, COALESCE(num_dups,0) AS num_dups
FROM
    documents d
LEFT JOIN
    (
        SELECT dup1.docid, dup1.dup_set, count(*) - 1 AS num_dups
        FROM duplicates dup1
        JOIN duplicates dup2 USING (dup_set)
        GROUP BY dup1.docid, dup1.dup_set
    ) ds
USING (docid)
WHERE num_dups IS NULL
ORDER BY dup_set, docid
;

ROLLBACK;

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