Re: BUG #17009: create temporary table with like option using same name as persistent table does not create indexes

> If you upgrade to 12.6 or 12.7, does it work?
Good afternoon, David.

After updating to 12.7, the bug really disappeared:

postgres=# select version();
                           version
------------------------------------------------------------
  PostgreSQL 12.7, compiled by Visual C++ build 1914, 64-bit
(1 строка)
postgres=# create table t_tmp (a int);
CREATE TABLE
postgres=# create index on t_tmp (a);
CREATE INDEX
postgres=#
postgres=# create temporary table t_tmp (like t_tmp including all);
CREATE TABLE
postgres=#
postgres=# select *
postgres-# from pg_catalog.pg_indexes
postgres-# where tablename  like 't_tmp%';
  schemaname | tablename |  indexname  | tablespace 
|                          indexdef
------------+-----------+-------------+------------+-------------------------------------------------------------
  public     | t_tmp     | t_tmp_a_idx |            | CREATE INDEX 
t_tmp_a_idx ON public.t_tmp USING btree (a)
  pg_temp_3  | t_tmp     | t_tmp_a_idx |            | CREATE INDEX 
t_tmp_a_idx ON pg_temp_3.t_tmp USING btree (a)
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Do I understand correctly that the solution in my case is to upgrade to 
at least 12.6?