Julien Cigar wrote:
>
> What I would like is a query that returns all the specimen_id of
> this table which have _all_ the given test_bit_id.
[snip]
> With the following I got a syntax error:
> select specimen_id
> from specimen_test_bits
> where test_bit_id = all(1,2,3,4);
It's expecting an array here. You'd have to write = all('{1,2,3,4}')
But that would have the same problem as...
> The following works but no rows are returned :
> select specimen_id
> from specimen_test_bits
> where test_bit_id = all(select id from test_bits where id in (1,2,3,4));
It's testing each row individually and of course one row can't match ALL
four values.
What you want to do is count the distinct values. Something like:
SELECT specimen_id
FROM foo
GROUP BY specimen_id
HAVING count(distinct test_bit_id) = 4
;
-- Richard Huxton Archonet Ltd