Andrus wrote:
> How to create function which returns persons age in years?
>
> Function parameters:
>
> ldDob - Day Of birth
> ldDate - Day where age is returned
>
>
> I tried
> CREATE OR REPLACE FUNCTION public.age(date, date, out integer) IMMUTABLE AS
> $_$
> SELECT floor(INT($2::text::integer-$1::text::integer)/10000);
> $_$ language sql
There's already an age(timestamp [, timestamp]) function available for this:
select age('1912-06-23'::date);
or
select age(now()::date, '1912-06-23'::date);
And if you want just the number of years, use date_part to extract just
that piece:
select date_part('year', age(now()::date, '1912-06-23'::date));
Based on this and your other question about functions that followed, you
may want to read the Date and Time Functions section of the docs:
http://www.postgresql.org/docs/8.2/interactive/functions-datetime.html
-Jon
--
Senior Systems Developer
Media Matters for America
http://mediamatters.org/