Re: SQL Question - Using Group By

ksherlock@gmail.com wrote:
> You could use COUNT() in conjunction with NULLIF:
>
> select "Type",
> count(nullif("Active", false)) as "Active Count",
> count(nullif("Active", true)) as "Inactive Count",
> 100 * count(nullif("Active", false)) / count(*) as "Active Percent"
> from table_name group by "Type"

Tom Lane suggested me to use sum("Active"::int) in a similar situation;
Except that I had boolean expressions instead of values. It is a bit
faster; IMO readability is just "different".

--
Alban Hertroys
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