Re: avg(interval)

Tom Lane wrote:
> "Jeremiah Elliott" <geek00@gmail.com> writes:
>> however if i don't average them here is what i get:
>> "7 days 22:24:50.62311";"*2420"
>> "9 days 22:21:02.683393";"*2420"
>> "23:21:35.458459";"*2420"
>> "4 days 22:47:41.749756";"*2420"
>> "3 days 06:05:59.456947";"*2420"
> 
>> which should average to just over nine days -
> 
> Uh ... how do you arrive at that conclusion?  I haven't done the math,
> but by eyeball an average of four-something days doesn't look out of
> line for those values.

It seems he's calculating (7 + 9 + 23 + 4 + 3) / 5 ...

Joe