Not sure if I have this the right way round, but one option is a self-join
select p2.first, p2.last, p1.first, p1.last
from people p1, people p2
where p1.person_id = p2.alias
and p2.isalias = true;
Another is to use a sub-select as a column result (haven't checked the
SQL for mistakes)
select p2.first, p2.last, (select first||' - '||last from person p1
where p2.alias = p1.person_id) as realname
from person p2
and p2.isalias = true;
Hope that helps as a starting point.
John
Jim Fitzgerald wrote:
> Hello -
>
> I'm trying to figure out how to write a particular query and need some
> assistance. I imagine this is extremely simple. I have the table defined
> below with five records. This table keeps track of peoples names. Each
> person has a unique ID number ("person_id"). The table can also keep track
> of alias names for these people. Each record has a flag ("isalias")
> indicating whether or not this record indicates a persons real name or a
> persons alias name. If it is an alias name then an additional field
> ("alias") has the number indicating this persons real name record by
> person_id (ie alias field of an alias record == the person_id of the real
> name record).
>
> I want a query that will select all entries where "isalias" is true and
> will display the person_id, first, and last fields from the alias record and
> ALSO the first and last fields from the real name entry.
>
> Output would be something like this for the example data below
>
> 3 - Johns - Alias - John - Smith
> 4 - Marks - Alias - Mark - Twain
>
>
> Any thoughts on how this can be accomplished easily / efficiently?
>
> Thanks
> -Jim
>
>
> Table "public.people"
> Column | Type | Modifiers
> -----------+-----------------------+-----------
> person_id | integer |
> first | character varying(20) |
> last | character varying(20) |
> alias | integer |
> isalias | boolean |
>
> Containing the example data:
>
> person_id | first | last | alias | isalias
> -----------+-------+-------+-------+---------
> 1 | John | Smith | 0 | f
> 2 | Mark | Twain | 0 | f
> 3 | Johns | Alias | 1 | t
> 4 | Marks| Alias | 2 | t
> 5 | someone | else | 0| f
>
> (5 rows)
>
>
>
>
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