Re: Why the planner is not using the INDEX .
От | David Gagnon |
---|---|
Тема | Re: Why the planner is not using the INDEX . |
Дата | |
Msg-id | 42C9D47E.7090103@siunik.com обсуждение исходный текст |
Ответ на | Re: Why the planner is not using the INDEX . (Stephan Szabo <sszabo@megazone.bigpanda.com>) |
Ответы |
Re: Why the planner is not using the INDEX .
(Christopher Kings-Lynne <chriskl@familyhealth.com.au>)
Re: Why the planner is not using the INDEX . (Bruno Wolff III <bruno@wolff.to>) Re: Why the planner is not using the INDEX . (Stephan Szabo <sszabo@megazone.bigpanda.com>) |
Список | pgsql-performance |
Thanks .. I miss that FK don't create indexed ... since Primary key implicitly does ...
I'm a bit surprised of that behavior thought, since it means that if we delete a row from table A all tables (B,C,D) with FK pointing to this table (A) must be scanned.
If there is no index on those tables it means we gone do all Sequantial scans. Than can cause significant performance problem!!!.
Is there a reason why implicit index aren't created when FK are declared. I looked into the documentation and I haven't found a way to tell postgresql to automatically create an index when creating la FK. Does it means I need to manage it EXPLICITLY with create index statement ? Is there another way ?
Thanks for you help that simple answer will solve a lot of performance problem I have ...
/David
I'm a bit surprised of that behavior thought, since it means that if we delete a row from table A all tables (B,C,D) with FK pointing to this table (A) must be scanned.
If there is no index on those tables it means we gone do all Sequantial scans. Than can cause significant performance problem!!!.
Is there a reason why implicit index aren't created when FK are declared. I looked into the documentation and I haven't found a way to tell postgresql to automatically create an index when creating la FK. Does it means I need to manage it EXPLICITLY with create index statement ? Is there another way ?
Thanks for you help that simple answer will solve a lot of performance problem I have ...
/David
On Mon, 4 Jul 2005, David Gagnon wrote:If you can just help my understanding the choice of the planner. Here is the Query:explain analyse SELECT IRNUM FROM IR INNER JOIN IT ON IT.ITIRNUM = ANY ('{1000, 2000}') AND IT.ITYPNUM = 'M' AND IR.IRYPNUM = IT.ITYPNUM AND IR.IRNUM = IT.ITIRNUM WHERE IRNUM = ANY ('{1000, 2000}') and IRYPNUM = 'M' Here is the Query plan: QUERY PLAN Hash Join (cost=1142.47..5581.75 rows=87 width=4) (actual time=125.000..203.000 rows=2 loops=1) Hash Cond: ("outer".itirnum = "inner".irnum) -> Seq Scan on it (cost=0.00..3093.45 rows=31646 width=9) (actual time=0.000..78.000 rows=2 loops=1) Filter: ((itirnum = ANY ('{1000,2000}'::integer[])) AND ((itypnum)::text = 'M'::text)) -> Hash (cost=1142.09..1142.09 rows=151 width=37) (actual time=125.000..125.000 rows=0 loops=1) -> Index Scan using ir_pk on ir (cost=0.00..1142.09 rows=151 width=37) (actual time=0.000..125.000 rows=2 loops=1) Index Cond: ((irypnum)::text = 'M'::text) Filter: (irnum = ANY ('{1000,2000}'::integer[])) Total runtime: 203.000 msI don't understand why the planner do a Seq Scan (Seq Scan on table IT ..) instead of passing by the followin index: ALTER TABLE IT ADD CONSTRAINT IT_IR_FK foreign key (ITYPNUM,ITIRNUM) references IR (IRYPNUM, IRNUM) ON UPDATE CASCADE;That doesn't create an index on IT. Primary keys (and unique constraints) create indexes, but not foreign keys. Did you also create an index on those fields? Also it looks like it's way overestimating the number of rows that condition would succeed for. You might consider raising the statistics targets on those columns and reanalyzing.
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