people who buy A, also buy C, D, E
От | Dan Langille |
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Тема | people who buy A, also buy C, D, E |
Дата | |
Msg-id | 426D6D6F.7549.B12D9FC@localhost обсуждение исходный текст |
Ответы |
Re: people who buy A, also buy C, D, E
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Список | pgsql-sql |
The goal of my query is: given a book, what did other people who bought this book also buy? I plan the list the 5 most popular such books. In reality, this isn't about books, but that makes it easier to understand I think. We have a table of customer_id (watch_list_id) and book_id (element_id). freshports.org=# \d watch_list_element Table "public.watch_list_element" Column | Type | Modifiers ---------------+---------+-----------watch_list_id | integer | not nullelement_id | integer | not null Indexes: "watch_list_element_pkey" primary key, btree (watch_list_id, element_id) "watch_list_element_element_id" btree (element_id) Foreign-key constraints: "$2" FOREIGN KEY (watch_list_id) REFERENCES watch_list(id) ON UPDATE CASCADE ON DELETE CASCADE "$1" FOREIGN KEY (element_id) REFERENCES element(id) ON UPDATE CASCADE ON DELETE CASCADE freshports.org=# I have a query which returns the needed results: SELECT W.element_id FROM watch_list_element W WHERE w.watch_list_id in (select watch_list_id from watch_list_element where element_id = 54968) GROUP BY W.element_id ORDER BY count(W.watch_list_id) DESC LIMIT 5; But performance is an issue here. So I'm planning to calculate all the possible values and cache them. That is, given each element_id in a watch_list, what are the top 5 element_id values on all the lists on which the original element_id appears? I'm having trouble constructing the query. I'm not even sure I can do this in one select, but that would be nice. Examples and clues are appreciated. Any ideas? Thank you. -- Dan Langille : http://www.langille.org/ BSDCan - The Technical BSD Conference - http://www.bsdcan.org/ NEW brochure available at http://www.bsdcan.org/2005/advocacy/
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