INTERVAL in a function
| От | Ron St-Pierre | 
|---|---|
| Тема | INTERVAL in a function | 
| Дата | |
| Msg-id | 41900C26.1010500@syscor.com обсуждение исходный текст | 
| Ответы | Re: INTERVAL in a function | 
| Список | pgsql-general | 
I have a simple function which I use to set up a users' expiry date. If
a field in a table contains an interval then
this function returns a timestamp some time in the future (usually two
weeks), null otherwise. I can't pass the
interval from the table into a variable properly within the function.
Any ideas?
CREATE OR REPLACE FUNCTION getUnitTimeLength(int) RETURNS timestamp AS '
  DECLARE
    grpID ALIAS FOR $1;
    intval INTERVAL;
    exptime TIMESTAMP;
  BEGIN
    SELECT INTO intval unitTimeLength::INTERVAL FROM customer.groups WHERE groupsID = grpID;
    IF intval IS NULL THEN
      RETURN NULL;
    ELSE
      SELECT INTO exptime current_timestamp + INTERVAL ''intval'';
      RETURN exptime;
    END IF;
  END;
' LANGUAGE 'plpgsql';
SELECT getUnitTimeLength(55);
ERROR:  invalid input syntax for type interval: "intval"
CONTEXT:  PL/pgSQL function "getunittimelength" line 11 at select into variables
However if I change the else clause to this:
    ELSE
      SELECT INTO exptime current_timestamp;
      RETURN exptime;
    END IF;
it works:
----------------------------
 2004-11-08 16:14:40.273597
(1 row)
Thanks
Ron
		
	В списке pgsql-general по дате отправления: