Re: Complicated "group by" question
| От | Jean-Luc Lachance | 
|---|---|
| Тема | Re: Complicated "group by" question | 
| Дата | |
| Msg-id | 412CD247.5020706@sympatico.ca обсуждение исходный текст | 
| Ответ на | Complicated "group by" question (Andrew Perrin <clists@perrin.socsci.unc.edu>) | 
| Список | pgsql-sql | 
Andrew,
If assing is not a many to many relation,
why did you not fold accept_id into assign?
Any way, here is the query you need:
select assign.reviewer_id, ss.max_assign_date,  accept.assign_id, accept.accept_id
from (  select reviewer_id, max( assign_date) as max_assign_date  from assign group by reviewer_id) as ss, assign,
accept
where ss.reviewer_id = assign.reviewer_id  and ss.max_assign_date = assign.assign_date  and assign.assign_id =
accept.assign_id;
Andrew Perrin wrote:
> I have a table of people ("reviewers"), a table of review assignments
> ("assign"), and a table of review acceptances ("accept"). I would like to
> be able to write a query to return the latest (e.g., max(assign_date))
> assignment for each reviewer, plus the acc_id field from "accept".  I
> think I should be able to do this with a GROUP BY clause, but am having no
> luck.
> 
> Table structure:
> 
> reviewers    assign        accept
> -----------------------------------------
> reviewer_id    assign_id    accept_id
>         reviewer_id    assign_id
> ...        assign_date
>         ...        ...
> 
> 
> Thanks for any guidance.
> 
> Andy
> 
> ----------------------------------------------------------------------
> Andrew J Perrin - http://www.unc.edu/~aperrin
> Assistant Professor of Sociology, U of North Carolina, Chapel Hill
> clists@perrin.socsci.unc.edu * andrew_perrin (at) unc.edu
> 
> 
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