Re: Parsing Data, Table to Form

Hi Yasmine,

A lack of error checking has caught us out here. Plus some syntax in the
select and where clause.  The adid in admininfo table is an integer, and
I gave you code for using a character type key.
So change ... WHERE adid='$adid'   to  WHERE adid=$adid    (drop the ' )
While there you could add some error condition checking like below:

$rowtoupdate = pg_exec($database, "SELECT adid, name, sur, phone, email,
username, password, building, postcode                 FROM admininfo
WHERE adid=$adid");
if ( ! pg_numrows($rowstoupdate) == 1 )          // expecting a single
row only
{
       echo "<h2>Error in getting information from table</h2>";
       // add whatever you want here to help you see what went wrong
} else{
        list($formadid, $formname, $formsurname, $formphone, $formemail,
$formusername, $formpassword,
    $formbuilding,$formpostcode) = pg_fetch_row($rowtoupdate, 0);
}

Keep going you're getting close.


Yasmine Kedoo wrote:

> Hey Paul.
>
> Yes, the error is exactly that :-). I've put in the following code on
> admininfo.php:
>
> else
>             {
>
>                 $row = pg_fetch_object($result, 0);
>
>                 $test = "";
>
>                    for ($rw = 0; $rw < $maxrows; $rw++)
>                    {
>
>                     echo " <tr> ";
>
>                     for ($fld = 0; $fld < $maxfields ; $fld++)
>
>                     {
>
>
>                             /*echo "<td width=\"418\"
> class=\"tabletext\" height=\"38\">";
>
>
>                         echo "</td>";
>                         echo $test .= pg_Result($result,$rw,$fld);*/
>
>                         echo pg_Result($result,$rw,$fld);
>
>                     }
>
>                     /*echo "<td width=\"194\" class=\"tabletext\"
> height=\"38\"> </td> </tr>";*/
>
>
>                     pg_result($result,0,$adid);
>                     echo "<form method=post action=updaad.php>\n";
>                     echo "<input type=\"hidden\"
> name=\"adid\"value=\"$adid\" >";
>                     echo "<input type=\"hidden\"
> name=\"name\"value=\"$name\" >";
>                     echo "<input type=\"hidden\"
> name=\"surname\"value=\"$surname\" >";
>                     echo "<input type=\"hidden\"
> name=\"phone\"value=\"$phone\" >";
>                     echo "<input type=\"hidden\"
> name=\"email\"value=\"$email\" >";
>                     echo "<input type=\"hidden\"
> name=\"username\"value=\"$username\" >";
>                     echo "<input type=\"hidden\"
> name=\"password\"value=\"$password\" >";
>                     echo "<input type=\"hidden\"
> name=\"building\"value=\"$building\" >";
>                     echo "<input type=\"hidden\"
> name=\"postcode\"value=\"$postcode\" >";
>                     echo "<input type=\"submit\" value=\"Update\" >";
>                     echo "</form>";
>                    }
>             }
>
> and on page updaad.php, the error:
>
> Warning: Unable to jump to row 0 on PostgreSQL result index 2 in
> /home/webpages/yamkedoo/Project/updaad.php on line 66
>
> is displayed, along with empty textfields. The relevant code for
> updaad.php is as follows:
>
>                                                $adid =  $_POST['adid'];
>             $name =  $_POST['name'];
>             $surname =  $_POST['surname'];
>             $phone =  $_POST['phone'];
>             $email =  $_POST['email'];
>             $username =  $_POST['username'];
>             $password =  $_POST['password'];
>             $building =  $_POST['building'];
>             $postcode =  $_POST['postcode'];
>
>             $rowtoupdate = pg_exec($database, "SELECT adid, name, sur,
> phone, email, username, password, building, postcode FROM admininfo
> WHERE adid='$adid'");
>
> list($formadid, $formname, $formsurname, $formphone, $formemail,
> $formusername, $formpassword, $formbuilding,$formpostcode) =
> pg_fetch_row($rowtoupdate, 0);
>
>             echo "<form method=post action=adupdate.php>\n";
>             echo "Admin ID Number: <input type=text name=\"formadid\"
> value=\"$formadid\"><br />\n";
>             echo "Name: <input type=text name=\"formname\"
> value=\"$formname\"><br />\n";
>             echo "Surname: <input type=text name=\"formsurname\"
> value=\"$formsurname\"><br />\n";
>             echo "Phone: <input type=text name=\"formphone\"
> value=\"$formphone\"><br />\n";
>             echo "Email: <input type=text name=\"formemail\"
> value=\"$formemail\"><br />\n";
>             echo "Username: <input type=text name=\"formusername\"
> value=\"$formusername\"><br />\n";
>             echo "Password: <input type=text name=\"formpassword\"
> value=\"$formpassword\"><br />\n";
>             echo "Building: <input type=text name=\"formbuilding\"
> value=\"$formbuilding\"><br />\n";
>             echo "Postcode: <input type=text name=\"formpostcode\"
> value=\"$formpostcode\"><br />\n";
>             echo "<BR>";
>             echo "<input type=\"submit\" value=\"Update\" >";
>             echo "</form>";
>
> I am not too sure how to fix the error on page admininfo.php. Any
> ideas? It doesn't seem to be parsing the data to the textfields.
>
> Thanx again,
>
> Yasmine
>
>
>> From: Paul Lynch <paul.lynch@exemail.com.au>
>> To: Yasmine Kedoo <yazkedoo@hotmail.com>,  pgsql-php@postgresql.org
>> Subject: Re: [PHP] Parsing Data, Table to Form
>> Date: Sun, 16 May 2004 22:14:15 +1000
>>
>> Hi Yasmine,
>>
>> Could you post line 66 or point out which line is 66 in updaad.php.
>> From the error message I would expect it to contain something like:
>> pg_fetch_row($rowtoupdate, 0)
>>
>> From your code, if this failed it would be before the display of data
>> in the form, and not after you click the update button. Which has me
>> a little perplexed.  In fact I would expect clicking on the update
>> button to start loading program adupdate.php
>> as per instructions in this line:
>>  echo "<form method=post action=adupdate.php>\n";
>> So unless this error was hidden somehow by the form and then
>> displayed after the click of update button, but that doesn't fit with
>> my knowledge of browser behaviour.
>>
>> I am hoping the content on line 66 and a bit above and below it can
>> help relate the error message to the code.
>>
>> Paul
>>
>> Yasmine Kedoo wrote:
>>
>>> but when i click the submit button on updaad.php, i'm getting the
>>> following error :
>>>
>>> Warning: Unable to jump to row 0 on PostgreSQL result index 2 in
>>> /home/webpages/yamkedoo/Project/updaad.php on line 66
>>>
>>> and nothing is being parsed to the textfields on adupdate.php
>>> (writeat.php).
>>>
>>> Do u know wat the problem may be? :-)
>>>
>>> Thanx again, your help is much appreciated
>>>
>>> Yasmine
>>
>>
>>
>
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