Re: UPDATE - Changing Password

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От Robby Russell
Тема Re: UPDATE - Changing Password
Дата
Msg-id 4081A448.4070204@commandprompt.com
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Ответ на UPDATE - Changing Password  ("Yasmine Kedoo" <yazkedoo@hotmail.com>)
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Yasmine Kedoo typed this on 04/17/2004 02:28 PM:
> Hi.
>
> Does anyone know how to use UPDATE with PHP for changing a password?
> I've tried the following code:
>
> $query = "UPDATE patperinfo SET trim(password)='$newpw' WHERE
> trim(gpid)='$gpidno'";
> $result = pg_exec($database, $query);
>
> where new $newpw & $gpidno are the values entered into a form then
> passed to the script.
>
> I get the following error:
>
> Warning: PostgreSQL query failed: ERROR: parser: parse error at or near
> "(" at character 27 in /home/webpages/yamkedoo/Tests/chpw1.php on line 48
>
> where the error is on the line: $result = pg_exec($database, $query);
>
>

$query = "UPDATE tablename SET password = '$newpw'  WHERE ...

I don't know why you'd trim a fieldname while setting it.

-Robby

--
Robby Russell,  |  Sr. Administrator / Lead Programmer
Command Prompt, Inc.   |  http://www.commandprompt.com
rrussell@commandprompt.com | Telephone: (503) 667.4564

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