Re: comparring dates between perl and postgres

I have never used extract.  This generates a syntax error when I added
and select extract( DOY FROM date)

    $sth = $dbh->prepare("SELECT date,address,time,host,direction,description,
       cal,reminder from firesides and select extract( DOY FROM date)
       where date > '$dstr1' and date <= '$dstr2'");
    if ($sth->execute)
    {
# assign each query record to an array
        $numrow = 0;
     while
        (($date,$address,$time,$host,$directions,$description,$cal,$reminder,
$db_doy) = $sth->fetc\
hrow)

Tom

On 4 Dec 2003 at 2:56, SaiHertz And Control Systems wrote:

> hodges@xprt.net wrote:
>
> >I am getting a field of date type from PostgreSQL and an
> >integer that is a number of days (1 to 3).
> >
> >select date, num_days from table
> >$date, $num_days
> >
> >In my perl script I am getting the current date
> >
> >#find current date
> >($mday,$mon,$year,$doy)=(localtime(time))[3..5,7];
> >$mon ++;
> >$year +=1900;
> >$today = "$year-$mon-$mday";
> >
> >
>
> I dont know about perl but Postgresql will do it for you as
> mypromt:#SELECT EXTRACT(DOY FROM DATE '2003-12-25')
> date_part
> ----------------------
> 359
>
> 1 Row(s) affected
>
> Shoot back if this helps !
>
> Regards,
> V Kashyap
>
>
>
>
>