Re: GPL code issue?

Dave Page wrote:

>/* A Bison parser, made by GNU Bison 1.875.  */
>
Given that this file appears to be produced *by* Bison, and given this
exception:

>/* As a special exception, when this file is copied by Bison into a
>   Bison output file, you may use that output file without restriction.
>   This special exception was added by the Free Software Foundation
>   in version 1.24 of Bison.  */
>
it would appear that the file can be used without restriction.  Any
output from bison or flex is non-GPL, AIUI.  Any input *into* bison,
which is GPL'd before processing, *is* restricted.  Given that bison
doesn't take .h files as input, doesn't it make sense that this was
produced *by* bison, and thus unrestricted?

ahp