Re: how to get decimal to date form

> In our postgre database is a decimal field with format YYMMDDhhmmss.9999999999
> where the 9s are random digits.  I'm trying to strip off just the
> YYMMDD and put it in date form.
> 
> So far I came up with:
> SUBSTR(TO_CHAR(rec_num,99999999999),1,6) AS Date which returns YMMDD.
> 
> For example where the rec_num is 30608124143.47069519725 the above
> functions return 30608.
> 
> I tried wrapping another TO_CHAR around it to try to format it to a
> date but this seems like it's a bit much for this purpose.
> 
> Any suggestions would be appreciated.
> 
> -David
1. replace 0 with 9 to get leading zeroes - 030608 instead of 30608

2. to_date('030608','YYMMDD');

Regards,
Tomasz Myrta