Hi,<br /><br /> Thank you kindly for your suggetions.<br /> Greg's suggestion was closest to what I needed ( spot on
infact ) <br /><br /> Cheers<br /> Rudi.<br /><br /><a class="moz-txt-link-abbreviated"
href="mailto:greg@turnstep.com">greg@turnstep.com</a>wrote:<br /><blockquote
cite="midea0824a43c82b86591e6b913514cf5ba@biglumber.com"type="cite"><pre wrap="">-----BEGIN PGP SIGNED MESSAGE-----
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</pre><blockquote type="cite"><pre wrap="">I've tries Left outer join's with and without coalesce without joy so far.
Please check out my query. </pre></blockquote><pre wrap="">
Your query is good, let's just make the whole thing a subselect
and use an outer join to get the missing sites:
SELECT u2.site_name, COALESCE(u1.total, 0)
FROM
( SELECT site_name, COUNT(cus_id) AS total FROM user_main um WHERE NOT EXISTS ( SELECT
cus_id FROM user_sys_messages usm WHERE usm.cus_id = um.cus_id ) GROUP BY site_name
) AS u1
RIGHT OUTER JOIN user_main u2 USING (site_name)
GROUP BY 1,2
ORDER BY u2.site_name;
You could also write this as a LEFT OUTER JOIN (by putting the subselect second),
but I think it is clearer if the USING or ON is as close as possible to the
JOIN statement.
- --
Greg Sabino Mullane <a class="moz-txt-link-abbreviated" href="mailto:greg@turnstep.com">greg@turnstep.com</a>
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</pre></blockquote><br /><br />