Re: forms /selects

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От angelo.rigo@globo.com
Тема Re: forms /selects
Дата
Msg-id 3DCBFE22000E94C8@riosf06.globoi.com
обсуждение исходный текст
Ответ на Re: forms /selects  (jco@cornelius-olsen.dk)
Ответы Re: forms /selects solution  (angelo.rigo@globo.com)
Список pgsql-php
Hi

I see my error was not using the "like"
but now i fall in other problem:

I have made an if else to display a message
if have no name with the selected leter as initial

it works but disply too:

Warning: Unable to jump to row 0 on PostgreSQL result index 2 in /var/www/html/inscricao/resultado_a1.php
on line 80

how could i handle this?

Thank?s in advance:

here is my actual code:

Pesquisa de nome por letra inicial
        <BR><form method="post" size="1" action="<?php print("$PHP_SELF"); ?>">
        <select size="1" name="letra">
                        <option selected>Escolha letra inicial
                        <option value=A>A
                        <option value=B>B
                        <option value=C>C
                        <option value=D>D
                        <option value=E>E
                        <option value=F>F
                        <option value=G>G
                        <option value=H>H
                        <option value=I>I
                        <option value=J>J
                        <option value=K>K
                        <option value=L>L
                        <option value=M>M
                        <option value=N>N
                        <option value=O>O
                        <option value=P>P
                        <option value=Q>Q
                        <option value=R>R
                        <option value=S>S
                        <option value=T>T
                        <option value=U>U
                        <option value=V>V
                        <option value=X>X
                        <option value=Y>Y
                        <option value=Z>Z
                        </select><input type="submit" value="Enviar"></form></TD>
      </TR>
      </TABLE> <br>
 <?php
$db = pg_connect("dbname=db user=user");
$query ="SELECT name FROM aprovados WHERE (nome like '$leter%') ORDER BY
name ASC ";
$result = pg_exec($db, $query);

if (!$result) {printf ("Não há nomes com esta letra inicial!"); exit;}
$numrows = pg_numrows($result);


/***********************
     actual problem
***********************/

if ($numrows=='0') {
    print("Não foram encontrados nomes iniciados por : $letra");
    print("<a href='javascript:history.back(-1);'><<Voltar</a>");
}
else

$row=0;
printf ("<table border=0>");
printf ("<tr bgcolor='#FFFF33'><td><b>Nome</b></td></tr>");
do
{
$myrow = pg_fetch_array ($result,$row);
    if($row  % 2)    {
        $bgcolor="#FFFF99";
        }
    else  {
        $bgcolor="";
        }
printf ("<tr bgcolor='$bgcolor'><td>%s</td></tr>",$myrow[nome]);
$row++;
}
while ($row < $numrows);
printf ("</table>");
pg_close($db);
?>






 '>'-- Mensagem Original --
 '>'To: pgsql-php@postgresql.org
 '>'Subject: Re: [PHP] forms /selects
 '>'From: jco@cornelius-olsen.dk
 '>'Date: Tue, 10 Dec 2002 15:03:33 +0100
 '>'
 '>'
 '>'I see a couple of errors, one of which is the source of your problem.
 '>'You write:
 '>'        "SELECT name FROM thetable WHERE (nome=$leter%) ORDER BY nome
ASC";
 '>'This would evaluate to
 '>'        "SELECT name FROM thetable WHERE (nome=A%) ORDER BY nome ASC";
 '>'
 '>'What you need to write is:
 '>'        "SELECT name FROM thetable WHERE (nome like '$leter%') ORDER
BY nome
 '>'ASC";
 '>'
 '>'"like" is required to make regular expression match.
 '>'The quotes are always required when dealing with strings (and a few
other
 '>'
 '>'types).
 '>'
 '>'You could have just debugged this by
 '>'        echo $query;
 '>'
 '>'Also: Letter contains two t's. :)
 '>'
 '>'Regards
 '>'/Jørn Cornelius Olsen


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