hmm.. you could try..
for(var i=0; $dados = pg_fetch_array($limite, $i); i++) {
$nome = $dados["nome"];
echo "Name: $nome<BR>";
}
I believe your error is your not passing pg_fetch_array() the row you
wish to return. It *may* or may not work that way. But leaving it open
like that is sure to cause an error sooner or later.
Hope this helps
David
angelo.rigo@globo.com wrote:
>Hi i am trying to build
>previous and next links from a table selection, the code below stops working
>at the line which says :
>
>while ($dados = pg_fetch_array($limite)) {
> $nome = $dados["nome"];
> echo "Nome: $nome<br>";
>
>the warning says:
>Wrong parameter count for pg_fetch_array()
>
>i get this code from a php mysql and try to adapt to my needs, is that any
>parameter wrong? wich can be?
>
>
><?php
>
>$conn = pg_connect("dbname=sondagem user=postgres");
>?>
><?php
>$busca = "SELECT nome AS data FROM aprovados ORDER BY nome ASC ";
>?>
><?php
>$total_reg = "10"; // número de registros por página
>?>
><?php
>if (!$pagina) {
> $pc = "1";
>} else {
> $pc = $pagina;
>}
>?>
><?php
>$inicio = $pc - 1;
>$inicio = $inicio * $total_reg;
>?>
><?php
>$limite = pg_exec("$busca LIMIT $inicio,$total_reg");
>$todos = pg_exec("$busca");
>
>$tr = pg_numrows($todos); // verifica o número total de registros
>$tp = $tr / $total_reg; // verifica o número total de páginas
>
>// vamos criar a visualização
>while ($dados = pg_fetch_array($limite)) {
> $nome = $dados["nome"];
> echo "Nome: $nome<br>";
>}
>
>// agora vamos criar os botões "Anterior e próximo"
>$anterior = $pc -1;
>$proximo = $pc +1;
>if ($pc>1) {
> echo " <a href='?pagina=$anterior'><- Anterior</a> ";
>}
>echo "|";
>if ($pc<$tp) {
> echo " <a href='?pagina=$proximo'>Próxima -></a>";
>}
>?>
>
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