Re: [PATCH]Remove the redundant assignment
| От | Heikki Linnakangas |
|---|---|
| Тема | Re: [PATCH]Remove the redundant assignment |
| Дата | |
| Msg-id | 384b7a2d-019d-4209-a401-7efde686c20c@iki.fi обсуждение исходный текст |
| Ответ на | Re: [PATCH]Remove the redundant assignment (Dagfinn Ilmari Mannsåker <ilmari@ilmari.org>) |
| Список | pgsql-hackers |
On 16/12/2025 13:16, Dagfinn Ilmari Mannsåker wrote:
>
> A quick grep reveals a bunch of strncpy() calls followed by a '\0'
> assignment that could be replaced with strlcpy():
>
> $ rg -A1 strncpy|rg -B1 "= '\\\\0';"
> src/interfaces/libpq/fe-secure-openssl.c: strncpy(buf, conn->sslpassword, size);
> src/interfaces/libpq/fe-secure-openssl.c- buf[size - 1] = '\0';
I'm not sure what exactly this code does, but it seems prudent to zero
the unused bytes since we're dealing with a password.
> --
> src/bin/pgbench/pgbench.c: strncpy(*script, option, namelen);
> src/bin/pgbench/pgbench.c- (*script)[namelen] = '\0';
Yeah, this one could use strlcpy(). Or memcpy(). Or pstrndup().
> --
> doc/src/sgml/ecpg.sgml: strncpy(name_buf, v.sqlname.data, v.sqlname.length);
> doc/src/sgml/ecpg.sgml- name_buf[v.sqlname.length] = '\0';
> --
> doc/src/sgml/ecpg.sgml: strncpy(name_buf, v.sqlname.data, v.sqlname.length);
> doc/src/sgml/ecpg.sgml- name_buf[v.sqlname.length] = '\0';
> --
> src/interfaces/ecpg/ecpglib/execute.c: strncpy(newcopy, (char *) var->value, slen);
> src/interfaces/ecpg/ecpglib/execute.c- newcopy[slen] = '\0';
> --
> src/interfaces/ecpg/ecpglib/execute.c: strncpy(mallocedval, (char *) var->value, slen);
> src/interfaces/ecpg/ecpglib/execute.c- mallocedval[slen] = '\0';
> --
> src/interfaces/ecpg/ecpglib/execute.c: strncpy(newcopy, variable->arr, variable->len);
> src/interfaces/ecpg/ecpglib/execute.c- newcopy[variable->len] = '\0';
I don't know if these depend on the zero-padding...
> --
> src/backend/utils/adt/name.c: strncpy(NameStr(*name), str, NAMEDATALEN);
> src/backend/utils/adt/name.c- NameStr(*name)[NAMEDATALEN - 1] = '\0';
This one *does* require the zero-padding, there's a comment that says so:
> void
> namestrcpy(Name name, const char *str)
> {
> /* NB: We need to zero-pad the destination. */
> strncpy(NameStr(*name), str, NAMEDATALEN);
> NameStr(*name)[NAMEDATALEN - 1] = '\0';
> }
- Heikki
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