SELECT BUG

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От José Soares
Тема SELECT BUG
Дата
Msg-id 37CD03AA.BC08CD19@sferacarta.com
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Ответы Re: [HACKERS] SELECT BUG  (Tom Lane <tgl@sss.pgh.pa.us>)
Список pgsql-hackers
<tt>I think I found some bugs in SELECT...</tt><br /><tt>I have two tables MASTER1 and DETAIL1 both of them with only
onefield CODE</tt><br /><tt>of data type VARCHAR but MASTER1.CODE is 11 char long and DETAIL1.CODE 16 char
l</tt><tt></tt><p><tt>hygea=>\d master1</tt><br /><tt>Table    = master1</tt><br
/><tt>+----------------------------------+----------------------------------+-------+</tt><br/><tt>|             
Field              |              Type                | Length|</tt><br
/><tt>+----------------------------------+----------------------------------+-------+</tt><br/><tt>|
code                            | varchar()                        |    11 |</tt><br
/><tt>+----------------------------------+----------------------------------+-------+</tt><tt></tt><p><tt>hygea=>\d
detail1</tt><br/><tt>Table    = detail1</tt><br
/><tt>+----------------------------------+----------------------------------+-------+</tt><br/><tt>|             
Field              |              Type                | Length|</tt><br
/><tt>+----------------------------------+----------------------------------+-------+</tt><br/><tt>|
code                            | varchar()                        |    16 |</tt><br
/><tt>+----------------------------------+----------------------------------+-------+</tt><tt></tt><p><tt>--Ihave the
followingtest data into these tables:</tt><tt></tt><p><tt>hygea=> select * from master1;</tt><br /><tt>code</tt><br
/><tt>-----------</tt><br/><tt>a</tt><br /><tt>a1</tt><br /><tt>a13</tt><br /><tt>(3
rows)</tt><tt></tt><p><tt>hygea=>select * from detail1;</tt><br /><tt>code</tt><br /><tt>----------------</tt><br
/><tt>a13</tt><br/><tt>a13</tt><br /><tt>a1</tt><br /><tt>(3 rows)</tt><tt></tt><p><tt>--if I try to join these two
tablesI have the following (nothing):</tt><tt></tt><p><tt>hygea=> select m.*, d.* from master1 m, detail1 d where
m.code=d.code;</tt><br/><tt>code|code</tt><br /><tt>----+----</tt><br /><tt>(0 rows)</tt><br /><tt>--and now trying
withTRIM function... it works!</tt><tt></tt><p><tt>hygea=> select m.*, d.* from master1 m, detail1 d where
trim(m.code)=trim(d.code</tt><br/><tt>code       |code</tt><br /><tt>-----------+----------------</tt><br
/><tt>a13       |a13</tt><br /><tt>a13        |a13</tt><br /><tt>a1         |a1</tt><br /><tt>(3
rows)</tt><tt></tt><p><tt>--andlast another variation using aliases: (note that I forgot to change</tt><br /><tt>--
MASTER1with m and DETAIL1 with d:</tt><br /><tt>hygea=> select master1.*, detail1.* from master1 m, detail1 d where
trim(m.code)</tt><br/><tt>code       |code</tt><br /><tt>-----------+----------------</tt><br /><tt>a         
|a13</tt><br/><tt>a1         |a13</tt><br /><tt>a13        |a13</tt><br /><tt>a          |a13</tt><br /><tt>a1        
|a13</tt><br/><tt>a13        |a13</tt><br /><tt>a          |a1</tt><br /><tt>a1         |a1</tt><br /><tt>a13       
|a1</tt><br/><tt>a          |a13</tt><br /><tt>a1         |a13</tt><br /><tt>a13        |a13</tt><br /><tt>a         
|a13</tt><br/><tt>a1         |a13</tt><br /><tt>a13        |a13</tt><br /><tt>a          |a1</tt><br /><tt>a1        
|a1</tt><br/><tt>a13        |a1</tt><br /><tt>a          |a13</tt><br /><tt>a1         |a13</tt><br /><tt>a13       
|a13</tt><br/><tt>a          |a13</tt><br /><tt>a1         |a13</tt><br /><tt>a13        |a13</tt><br /><tt>a         
|a1</tt><br/><tt>a1         |a1</tt><br /><tt>a13        |a1</tt><br /><tt>(27 rows)</tt><tt></tt><p>Any ideas? <p>José
<br/>  

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