Re: Typo on tutorial window page

PG Doc comments form <noreply@postgresql.org> writes:
> EXPECTED:
> As shown here, the rank function produces a numerical rank for each distinct
> PARTITION BY value in the current row's partition, using the order defined
> by the ORDER BY clause. rank needs no explicit parameter, because its
> behavior is entirely determined by the OVER clause.

> ACTUAL:
> As shown here, the rank function produces a numerical rank for each distinct
> ORDER BY value in the current row's partition, using the order defined by
> the ORDER BY clause. rank needs no explicit parameter, because its behavior
> is entirely determined by the OVER clause.

Hmm, I think the current text is correct, or at least more nearly
correct than what you suggest.  Look at the example:

<programlisting>
SELECT depname, empno, salary,
       rank() OVER (PARTITION BY depname ORDER BY salary DESC)
FROM empsalary;
</programlisting>

<screen>
  depname  | empno | salary | rank
-----------+-------+--------+------
 develop   |     8 |   6000 |    1
 develop   |    10 |   5200 |    2
 develop   |    11 |   5200 |    2
 develop   |     9 |   4500 |    4
 develop   |     7 |   4200 |    5
 personnel |     2 |   3900 |    1
 personnel |     5 |   3500 |    2
 sales     |     1 |   5000 |    1
 sales     |     4 |   4800 |    2
 sales     |     3 |   4800 |    2
(10 rows)
</screen>

The ranks are separate within each partition (depname), and
within a partition rows having the same salary get the
same rank.

            regards, tom lane