Re: BUG #15724: Can't create foreign table as partition
| От | Tom Lane |
|---|---|
| Тема | Re: BUG #15724: Can't create foreign table as partition |
| Дата | |
| Msg-id | 21389.1553868091@sss.pgh.pa.us обсуждение исходный текст |
| Ответ на | Re: BUG #15724: Can't create foreign table as partition (Alvaro Herrera <alvherre@2ndquadrant.com>) |
| Ответы |
Re: BUG #15724: Can't create foreign table as partition
Re[2]: BUG #15724: Can't create foreign table as partition |
| Список | pgsql-bugs |
Alvaro Herrera <alvherre@2ndquadrant.com> writes:
> On 2019-Mar-29, PG Bug reporting form wrote:
>> SQL Error [42809]: ERROR: cannot create index on foreign table "msg_json"
> Ah, this is because we try to propagate the index to the partition,
> which appears to be less than desirable. Maybe this patch fixes it? I
> have not tested it, only verified that it compiles.
Really, what *ought* to happen in such a case is that the FDW gets
told about the command and has the opportunity to try to do something
corresponding to making an index. But that smells like a new feature
rather than a bug fix.
I'm not sure that just forcing the case to be a no-op is wise.
What if the index is supposed to be UNIQUE?
regards, tom lane
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