Re: FK violation in partitioned table after truncating a referencedpartition
| От | Alvaro Herrera |
|---|---|
| Тема | Re: FK violation in partitioned table after truncating a referencedpartition |
| Дата | |
| Msg-id | 20200206223015.GA32754@alvherre.pgsql обсуждение исходный текст |
| Ответ на | Re: FK violation in partitioned table after truncating a referencedpartition (Alvaro Herrera <alvherre@2ndquadrant.com>) |
| Ответы |
Re: FK violation in partitioned table after truncating a referencedpartition
|
| Список | pgsql-bugs |
On 2020-Feb-06, Alvaro Herrera wrote:
> I agree that patching heap_truncate_find_FKs is a reasonable way to fix.
> I propose a slightly different formulation: instead of the loop that you
> have, we can just use the second loop, and add more parent constraints
> to the list if any constraint we scan in turn has a parent constraint.
> So we don't repeat the whole thing, but only that second loop.
Hmm, this doesn't actually work; I modified your test case and I see
that my code fails to do the right thing.
-- Truncate a single partition cascading to another partitioned table.
CREATE TABLE trunc_a (a INT PRIMARY KEY) PARTITION BY RANGE (a);
CREATE TABLE trunc_a1 PARTITION OF trunc_a FOR VALUES FROM (0) TO (10);
CREATE TABLE trunc_a2 PARTITION OF trunc_a FOR VALUES FROM (10) TO (20)
PARTITION BY RANGE (a);
CREATE TABLE trunc_a21 PARTITION OF trunc_a2 FOR VALUES FROM (10) TO (12);
CREATE TABLE trunc_a22 PARTITION OF trunc_a2 FOR VALUES FROM (12) TO (16);
CREATE TABLE trunc_a2d PARTITION OF trunc_a2 DEFAULT;
CREATE TABLE trunc_a3 PARTITION OF trunc_a FOR VALUES FROM (20) TO (30);
INSERT INTO trunc_a VALUES (10), (15), (20), (25);
CREATE TABLE ref_c (
c INT PRIMARY KEY,
a INT REFERENCES trunc_a(a) ON DELETE CASCADE
) PARTITION BY RANGE (c);
CREATE TABLE ref_c1 PARTITION OF ref_c FOR VALUES FROM (100) TO (200);
CREATE TABLE ref_c2 PARTITION OF ref_c FOR VALUES FROM (200) TO (300);
INSERT INTO ref_c VALUES (100, 10), (150, 15), (200, 20), (250, 25);
TRUNCATE TABLE trunc_a21 CASCADE;
SELECT a as "from table ref_c" FROM ref_c;
SELECT a as "from table trunc_a" FROM trunc_a ORDER BY a;
DROP TABLE trunc_a, ref_c;
--
Álvaro Herrera https://www.2ndQuadrant.com/
PostgreSQL Development, 24x7 Support, Remote DBA, Training & Services
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