Re: index problems (again)

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От Peter J. Holzer
Тема Re: index problems (again)
Дата
Msg-id 20160307204022.GG28254@rorschach.hjp.at
обсуждение исходный текст
Ответ на Re: index problems (again)  (Geoff Winkless <pgsqladmin@geoff.dj>)
Ответы Re: index problems (again)  (Geoff Winkless <pgsqladmin@geoff.dj>)
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On 2016-03-07 16:37:37 +0000, Geoff Winkless wrote:
> On 7 March 2016 at 16:02, Tom Lane <tgl@sss.pgh.pa.us> wrote:
> > In English, what that plan is trying to do is scan the index
> > in sc_id order until it hits a row with scdate in the target range.
> > The first such row, by definition, has the correct min(sc_id) value.
> > The problem is that we're guessing at how soon we'll hit such a row.
> > If the columns are independent, then the planner can guess based on how
> > many rows in the whole table have scdate in the target range, and it
> > will probably be about right.  But that estimate can fall down very
> > badly if sc_id and scdate increase together, because then the target
> > rows aren't randomly distributed in the index sequence but could all be
> > all the way at the far end of the index.
>
> I'm sorry, I'm obviously not being clear. I already accepted this
> argument when Victor gave it, although I believe that in part it falls
> down because sc_id is also (potentially) randomly distributed so it's
> not like you're doing a sequential table scan (it might work better on
> a clustered table, but we don't have those :) )
>
> So you still have an extra layer of indirection into a large table
> with lots of random accesses.
>
> > If we had cross-column correlation stats we could detect this pitfall,
> > but without that it's hard to do.
>
> But as far as I can see, apart from the absolute extremes, the
> index-only scan is _always_ going to be quicker than the index+table
> scan.

We are talking about an "absolute extreme" here. You have about 420 date
values and you are looking for 3 of them. Assuming for the moment that
your distribution is uniform, that's 140th of the whole table.

So if PostgreSQL were using the (sc_date,sc_id) index, it would have so
scan 4E6/140 = 29000 index entries, extract the id value and get the
minumum of those 29000 values.

OTOH, if it uses the sc_id index, it only expects to have to scan 140
entries until it finds a matching entry. And then it is finished.

So it's 140 index entries plus row accesses against 29000 index entries.
To choose the second plan, the planner would have to estimate that
reading a random row is more than 200 times slower than reading an index
entry, which apparently it doesn't.

As Tom wrote, the estimate of having to read only about 140 rows is only
valid if sc_id and sc_date are uncorrelated. In reality your query has
to read a lot more than 140 rows, so it is much slower.


> I don't believe you need any further statistics than what is currently
> available to be able to make that judgement, and that's why I believe
> it's suboptimal.

We all know it is suboptimal, but unfortunately, without additional
statistics I don't think there is a better way. The other way around -
assuming that the columns are correlated in the worst possible way -
would remove viable plans in many cases.

This is, I think one of the places where hints are a good idea. The
programmer sometimes knows more about the characteristics of the data
than the planner can possibly know and it is a pity that there is no way
for the programmer to pass that knowledge to the planner. (And yes, I
know that quite often the programmer is wrong - but I do believe in
giving people enough rope to hang themselves with)

        hp

--
   _  | Peter J. Holzer    | I want to forget all about both belts and
|_|_) |                    | suspenders; instead, I want to buy pants
| |   | hjp@hjp.at         | that actually fit.
__/   | http://www.hjp.at/ |   -- http://noncombatant.org/

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