Re: There can be only one

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От Andreas Kretschmer
Тема Re: There can be only one
Дата
Msg-id 20151011112809.GA6083@tux
обсуждение исходный текст
Ответ на Re: There can be only one  (Andreas Kretschmer <andreas@a-kretschmer.de>)
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Andreas Kretschmer <andreas@a-kretschmer.de> wrote:

> Create a partial unique index on is_default.

as an example:


test=# CREATE TABLE payment_via (
  id            int PRIMARY KEY,
  provider      text NOT NULL,
  keys          hstore NOT NULL DEFAULT '',
  is_default    boolean NOT NULL DEFAULT FALSE
);
CREATE TABLE
test=*# create unique index idx_default on payment_via(is_default) where
is_default;
CREATE INDEX
test=*# insert into payment_via values (1, 'foo','', true);
INSERT 0 1
test=*# insert into payment_via values (2, 'bla','', false);
INSERT 0 1
test=*# insert into payment_via values (3, 'blubb','', true);
ERROR:  duplicate key value violates unique constraint "idx_default"
DETAIL:  Key (is_default)=(t) already exists.
test=*#




Andreas
--
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