Re: obtain the difference between successive rows

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От Kevin Grittner
Тема Re: obtain the difference between successive rows
Дата
Msg-id 20121123230326.297040@gmx.com
обсуждение исходный текст
Ответ на obtain the difference between successive rows  (ochaussavoine <olivier.chaussavoine@gmail.com>)
Список pgsql-general
Jasen Betts wrote:

> electricity meter may bis a bad example as usage meters often have
> fewer digits than are needed to track all historical usage
>
> eg:
>
>  '2012-05-07',997743
>  '2012-06-06',999601
>  '2012-07-05',000338
>  '2012-08-06',001290
>  '2012-09-07',002158
>  '2012-10-05',003018

Wrap-around can be handled pretty easily. It's meter replacement
that is a challenge.  :-)

SELECT
    current_reading_date as "reading date",
    lag(current_meter_reading, 1)
      over (order by current_reading_date) as "prior reading",
    current_meter_reading as "current reading",
    (1000000000 + current_meter_reading
      - lag(current_meter_reading, 1)
          over (order by current_reading_date)) % 1000000 as usage
  from electricity;

 reading date | prior reading | current reading | usage
--------------+---------------+-----------------+-------
 2012-05-07   |               |          997743 |      
 2012-06-06   |        997743 |          999601 |  1858
 2012-07-05   |        999601 |             338 |   737
 2012-08-06   |           338 |            1290 |   952
 2012-09-07   |          1290 |            2158 |   868
 2012-10-05   |          2158 |            3018 |   860
(6 rows)

-Kevin


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