Re: GROUP and ORDER BY

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От Tarlika Elisabeth Schmitz
Тема Re: GROUP and ORDER BY
Дата
Msg-id 20111108095958.2b6f3ad9@dick.coachhouse
обсуждение исходный текст
Ответ на Re: GROUP and ORDER BY  (Robins Tharakan <robins.tharakan@comodo.com>)
Ответы Re: GROUP and ORDER BY
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On Tue, 08 Nov 2011 09:57:08 +0530
Robins Tharakan <robins.tharakan@comodo.com> wrote:

>On 11/08/2011 02:50 AM, Tarlika Elisabeth Schmitz wrote:
>> Hello,
>>
>> I would like to GROUP the result by one column and ORDER it by
>> another:
>>
>> SELECT
>>      no, name, similarity(name, 'Tooneyvara') AS s
>>      FROM vtown
>>      WHERE    similarity(name, 'Tooneyvara')>  0.4
>>      ORDER BY s DESC
>>
>> Result:
>>
>> 1787    "Toomyvara"    0.5
>> 1787    "Toomevara"    0.4
>> 1188    "Toonybara"    0.4
>>
>>
>> Desired result:
>>
>> 1787    "Toomyvara"    0.5
>> 1188    "Toonybara"    0.4
>>
>> Gets rid of the  duplicate "no" keeping the spelling with the greater
>> similarity and presents the remaining result ordered by similarity.
>>
>>[...]

>[...] does this work ?
>
>SELECT no, name, MAX(similarity(name, 'Tooneyvara')) AS sim
>FROM vtown
>WHERE similarity(name, 'Tooneyvara') > 0.4
>GROUP BY no, name
>ORDER BY sim DESC
>
>--
>Robins Tharakan

Thank you for yuor suggestion, Robins. Unfortunately, it does not work;
this returns:
1787    "Toomyvara"    0.5
1787    "Toomevara"    0.4
1188    "Toonybara"    0.4
because while column "no" is identical, "name" isn't and you're
grouping by both of them.


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