Re: SQL Query Help Please !

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От Sam Mason
Тема Re: SQL Query Help Please !
Дата
Msg-id 20100706153509.GT7584@samason.me.uk
обсуждение исходный текст
Ответ на SQL Query Help Please !  (GrGsM <shaik2@navionicsindia.com>)
Список pgsql-general
On Tue, Jul 06, 2010 at 12:06:06AM -0700, GrGsM wrote:
>   SELECT   closedate,status,
>            SUM (CASE WHEN empcode = 'NT-028' THEN 1 ELSE 0 END) AS NT028,
>            SUM (CASE WHEN empcode = 'NT-031' THEN 1 ELSE 0 END) AS NT031,
>            SUM (CASE WHEN empcode = 'NT-050' THEN 1 ELSE 0 END) AS NT050,
>            SUM (CASE WHEN empcode = 'NT-062' THEN 1 ELSE 0 END) AS NT062
>         FROM   dbcleaning
>    WHERE   status = 'Fixed'
>            AND empcode IN
>                     ('NT-028',
>                      'NT-031',
>                      'NT-050',
>                      'NT-062')
> GROUP BY   closedate, status
>
> Now i need a column in the same result of the query which shows the
> difference between the two columns .
>
> For Example :
> the result shoud be
> Closedate , status ,  NT028, NT031, NT050,NT062 , NT028-NT031

Just put your code above in an "inner select", something like:

  SELECT closedate, status, NT028-NT031 AS diff
  FROM (
    SELECT closedate,status, SUM(CASE WHEN ...
    ...
    GROUP BY closedate, status) x;

--
  Sam  http://samason.me.uk/

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