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On Fri, Jun 26, 2009 at 05:03:11PM +0200, Dimitri Fontaine wrote:
> Le 26 juin 09 à 14:47, Jeremy Kerr a écrit :
>> For the new function to be faster, we need to know that there are more
>> than 6 (on average, depending on alignment) trailing spaces.
>
> It's becoming somewhat tricky, but maybe the test to do for the
> optimisation to get used is n >= threshold && str[n-6] == 0x20, àla
> Boyer/Moore?
That's cute. What about comparing the last aligned word which completely
fits in the buffer? Something along the lines of (assuming four-byte
words)
* (int*) (4 * ((int) &buf[0]) / 4)
(now that's an ugly one, but you know what I mean?)
Regards
- -- tomás
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