* Robert Haas (robertmhaas@gmail.com) wrote:
> I see that... but I don't think the test in the first loop is correct.
> It's based on the value of i % 4, but I'm not convinced that you know
> anything about the alignment at the point where i == 0.
Ah, you may be half right there (see below). It does appear to be
assuming that char *s (or s[i == 0]) is aligned, which isn't a
guarentee (in fact, it might never be right..). If having it actually
aligned is an important bit (as opposed to just doing the comparisons in
larger but possibly unaligned blocks) then that'd make a difference.
If the code as-is showed performance improvment even when it's working
on less-than-aligned blocks, I'd be curious what would happen if it was
actually aligned. Unfortunately, the results of such would probably be
heavily architecture dependent..
> > On the flip side, I am curious as to if the arguments to a stored
> > procedure are always aligned or not. Never had a case to care before,
> > but if palloc() is always going to return an aligned chunk of memory
> > (per MemSetAligned in c.h) it makes me wonder.
>
> Well, if it's char(n) for n <~ 126, it's going to have a 1-byte
> varlena header...
Right, but I'm talking about the base of the argument itself, not
the start of the data. If every variable length argument to a stored
procedure is palloc()'d independently, and palloc()'s always return
aligned memory, we'd at least know that the base of the argument is
aligned and could figure out the header size and then do the
comparisons accordingly. This would also mean, of course, that we'd
almost(?) never have s[i == 0] on an aligned boundary due to the
header.
Thanks,
Stephen