BUG #1733: Function visibility in transactions error
| От | Robert Grabowski |
|---|---|
| Тема | BUG #1733: Function visibility in transactions error |
| Дата | |
| Msg-id | 20050627150700.40D27F0B19@svr2.postgresql.org обсуждение исходный текст |
| Ответы |
Re: BUG #1733: Function visibility in transactions error
|
| Список | pgsql-bugs |
The following bug has been logged online:
Bug reference: 1733
Logged by: Robert Grabowski
Email address: grabba@env.pl
PostgreSQL version: 8.0.1
Operating system: Linux 2.6.12-gentoo
Description: Function visibility in transactions error
Details:
I have problem with function visibility in transaction when I do create and
drop function. There is an example.
I have two sessions:
1: CREATE FUNCTION test () RETURNS integer AS 'select 1' LANGUAGE 'sql';
CREATE FUNCTION
1: SELECT test();
test
------
1
(1 row)
2: BEGIN TRANSACTION ISOLATION LEVEL SERIALIZABLE;
BEGIN
2: SELECT test();
test
------
1
(1 row)
1: DROP FUNCTION test ();
DROP FUNCTION
1: CREATE FUNCTION test () RETURNS integer AS 'select 2' LANGUAGE 'sql';
CREATE FUNCTION
1: SELECT test();
test
------
2
(1 row)
2: SELECT test();
test
------
1
(1 row)
It's ok. In transaction I have old definition of test function.
2: SELECT test();
test
------
2
(1 row)
!!!! Strange! Second call of the same function gets other result.
In READ COMMITED transactions I have the same results.
В списке pgsql-bugs по дате отправления: