Re: BUG #1550: LOCK TABLE in plpgsql function doesn't work.
| От | Michael Fuhr |
|---|---|
| Тема | Re: BUG #1550: LOCK TABLE in plpgsql function doesn't work. |
| Дата | |
| Msg-id | 20050318063743.GA26191@winnie.fuhr.org обсуждение |
| Ответ на | BUG #1550: LOCK TABLE in plpgsql function doesn't work. ("Spencer Riddering" <spencer@riddering.net>) |
| Список | pgsql-bugs |
On Thu, Mar 17, 2005 at 08:48:54AM +0000, Spencer Riddering wrote:
> When a LOCK TABLE statement is included in a plpgsql function it does not
> actually lock the table.
How did you determine that? It's not clear from the example you
posted, and your function has its LOCK statements commented out.
I ran simple tests in 7.4.7 and LOCK worked in a PL/pgSQL function.
Here's an example, run from psql:
CREATE TABLE foo (x integer);
CREATE FUNCTION locktest() RETURNS void AS '
BEGIN
LOCK TABLE foo IN SHARE ROW EXCLUSIVE MODE;
RETURN;
END;
' LANGUAGE plpgsql;
BEGIN;
SELECT locktest();
SELECT * FROM pg_locks;
relation | database | transaction | pid | mode | granted
----------+----------+-------------+-------+-----------------------+---------
16759 | 17144 | | 26277 | AccessShareLock | t
| | 19353 | 26277 | ExclusiveLock | t
19293 | 17144 | | 26277 | ShareRowExclusiveLock | t
(3 rows)
If I try to acquire a conflicting lock in another transaction, it
blocks and pg_locks then looks like this:
relation | database | transaction | pid | mode | granted
----------+----------+-------------+-------+-----------------------+---------
19293 | 17144 | | 26274 | ShareRowExclusiveLock | f
16759 | 17144 | | 26277 | AccessShareLock | t
| | 19353 | 26277 | ExclusiveLock | t
19293 | 17144 | | 26277 | ShareRowExclusiveLock | t
| | 19354 | 26274 | ExclusiveLock | t
(5 rows)
> But, if prior to calling the function I execute a seperate statement using
> the same connection and same transaction then the LOCK TABLE does work.
>
> I think the expectation is that LOCK TABLE should actually lock the table
> even when included in a plpgsql function.
>
> I used JDBC (pg74.215.jdbc3.jar) to discover this behavior.
Is it possible that when you called the function without executing
anything beforehand, it was run in a transaction that ended sooner
than you were expecting? That would release any locks the function
had acquired.
--
Michael Fuhr
http://www.fuhr.org/~mfuhr/
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