Re: SQL question

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От Uwe C. Schroeder
Тема Re: SQL question
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Msg-id 200411080138.35835.uwe@oss4u.com
обсуждение исходный текст
Ответ на SQL question  ("Uwe C. Schroeder" <uwe@oss4u.com>)
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Thanks for your answers Greg & Vincent.
Although I solved the problem by a change of schema - I'm happy that I have
something to digest I didn't know before.  One never learns enough ...

U.C.

On Saturday 06 November 2004 03:13 pm, Uwe C. Schroeder wrote:
> Here's a question for the SQL guru's out there, which I've been trying to
> solve for the last couple of hours. There's got to be a solution to this,
> but somehow I can't find it.
>
> Tables:
>
> table1 (
>     uid int PK,
>         uname varchar(64)
> )
>
> table2 (
>     uid int FK to table1,
>         xuid int FK to table 1
> )
>
> table3 (
>       uid int FK to table1,
>     yuid int FK to table1
> )
>
> There might be more tables of the type like table2 and table3, but I'd
> already be happy to solve the puzzle with the 3 tables above.
> Ok, assume table1 is the master table - in my case a table used for login
> authentication (some columns removed above)
> table2 and table3 are tables where the uid always references to the uid in
> table1. The second "uid" (xuid and yuid in this example) references to
> another uid record in table1. The problem is that there may or may not be
> entries in table2 (or table3) referencing a specific uid in their second
> uid field.
> Maybe some data:
>
> table1:
> 1 test1
> 2 test2
> 3 test3
>
> table2:
> 1 2
> 1 3
> 3 1
>
> table3:
> 1 2
> 2 3
> 3 2
>
> What I want to do in a view is the following resultset:
>
> uid  uname xuid yuid
>  1    test1     2      2
>  1    test1     3
>  2    test2             3
>  3    test3      1
>  3    test3             2
>
>
> So basically I want to know which uid is connected to which uid, one
> relationship per row. So xuid and yuid shall be identical if records exist
> in both table2 and table3 or the value shall be NULL if a corresponding
> record can't be found in either table2 or table3.
>
> Can anyone here help me out?
>
> Thanks a lot
>
>     UC

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