Re: Referencing subselect returned value
| От | Bruno Wolff III |
|---|---|
| Тема | Re: Referencing subselect returned value |
| Дата | |
| Msg-id | 20040121181059.GA11684@wolff.to обсуждение исходный текст |
| Ответ на | Referencing subselect returned value (Marco Lazzeri <marcomail@noze.it>) |
| Список | pgsql-general |
On Tue, Jan 20, 2004 at 21:21:56 +0100, Marco Lazzeri <marcomail@noze.it> wrote: > I'd like to reference values returned by a subselect in the same SELECT > query. > > Example: > > SELECT id, > ( SELECT COUNT(*) FROM second ) AS value_to_reference, > ( value_to_reference + 1 ) AS value_that_uses_referenced_one > FROM first; > > Any suggestions? If you want to use a subselect repeatedly, you can either repeat it or join it. Doing a join will normally be better. Repeated select example: SELECT id, ( SELECT COUNT(*) FROM second) AS value_to_reference, ( SELECT COUNT(*) FROM second)+1 AS value_to_reference_one, FROM first; Join example: SELECT id, cnt AS value_to_reference, cnt+1 AS value_reference_one, FROM first, (select COUNT(*) AS cnt from second) AS third;
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