On Wed, 26 Jun 2002 22:18:07 +0200
Dennis Kaarsemaker <fake_adress@use-reply.to> wrote:
> From a copy of the CDDB-database i want to select the artist & album that
> has on average the longest tracks.
>
> But in the tracks table there is no such field as length, so i have to
> calculate it. But when i try to do so it just gives me errors.
>
> This is the erroneous query i have made so far
>
> select albums.ARTIST, albums.TITLE from tracks,albums
> where tracks.DISCID = albums.DISCID
> group by tracks.DISCID
> having(albums.LENGTH/count(tracks.TRACK)) =
> (
> select max(albums.LENGTH/count(tracks.TRACK)) from tracks,albums
> where tracks.DISCID = albums.DISCID
> group by tracks.DISCID
> );
>
> What is the correct way of selecting the album?
As for this query, some columns, AERIST, TITLE, and LENGTH, are lacking
at the GROUP BY clauses. Probably, I would think a nearly correct one is
something like the following.
SELECT a1.ARTIST, a1.TITLE
FROM (SELECT a0.DISCID, a0.ARTIST, a0.TITLE FROM tracks AS t0, albums AS a0 WHERE t0.DISCID = a0.DISCID
GROUP BY a0.DISCID, a0.ARTIST, a0.TITLE , a0.LENGTH HAVING a0.LENGTH /COUNT(t0.TRACK) = (SELECT
max(mx.average) FROM (SELECT albums.DISCID,
albums.LENGTH/COUNT(tracks.TRACK) AS average
FROM tracks, albums WHERE tracks.DISCID = albums.DISCID
GROUP BY albums.DISCID, albums.LENGTH ) AS mx ) )
ASa1
Regards,
Masaru Sugawara