Re: Optimization, etc

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От Stephan Szabo
Тема Re: Optimization, etc
Дата
Msg-id 20011109074346.L57927-100000@megazone23.bigpanda.com
обсуждение исходный текст
Ответ на Optimization, etc  ("Jeff Sack" <sackj@alum.rpi.edu>)
Ответы Re: Optimization, etc  (Jason Earl <jason.earl@simplot.com>)
Re: Optimization, etc  (Masaru Sugawara <rk73@echna.ne.jp>)
Список pgsql-sql
On Fri, 9 Nov 2001, Jeff Sack wrote:

> To find the names of the single season home run leaders, along with the
> total number of home runs, the team name/city and the year:
>
> select P.first_name, P.last_name, B.hr, T.name, T.city, S.year from
> statistics S, batting_stats B, players P, teams T
> where (S.id=B.id) and
> (S.player_id=P.id) and
> (B.hr>30) and
> (T.id=S.team_id) limit 10;
>
> You get the idea.  These queries take a while.  Is this just the way it
> is or there things that can be done to optimize this?

As a starting point, have you run vacuum analyze and what does
explain show for the query.  Also, do you have indexes on fields that
you're limiting on (like hr, etc...).

> One separate issue (the reason why the above examples are all about
> batting statistics) I'm having is representing the innings pitched
> statistic.  The way it is often represented (and the way it is done in
> this schema) is something like this 123.0 means exactly 123 innings
> pitched, 123.1 means 123 1/3 innings, and 123.2 means 123 2/3 innings
> pitched.  I'm contemplating the best way to write a function that knows
> how to sum these values accurately.  Is this something that can be done
> with PL/PGSQL or should I go straight to something like PLPERL?
> Alternatively, I could research a way to represent fractions in the DB
> and write a script to convert all values in this column.  Any advice
> here??

You'd probably be best off doing the conversion at insert time into an
additional field assuming that inserts are much less likely that
selects on your data.

(col-floor(col)*(10/3::numeric) seems to get back an appropriate value
but is probably reasonably expensive.




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