Re: showing also value '0' with aggregate count()

Поиск
Список
Период
Сортировка
От wsheldah@lexmark.com
Тема Re: showing also value '0' with aggregate count()
Дата
Msg-id 200109271534.LAA11176@interlock2.lexmark.com
обсуждение исходный текст
Ответ на showing also value '0' with aggregate count()  (Janning Vygen <vygen@planwerk6.de>)
Список pgsql-general

You need a left outer join:

select name, count(sales.client_id) from clients left outer join sales on
sales.client_id = clients.id group by name;

Outer joins were not supported prior to 7.1, so if you're using an earlier
version, you'll want to either upgrade or read the docs for your version; they
had a standard workaround prior to 7.1.

Wes Sheldahl




Janning Vygen <vygen%planwerk6.de@interlock.lexmark.com> on 09/27/2001 10:51:45
AM

To:   "PostgreSQL-General" <pgsql-general%postgresql.org@interlock.lexmark.com>
cc:    (bcc: Wesley Sheldahl/Lex/Lexmark)
Subject:  [GENERAL] showing also value '0' with aggregate count()


I need some help please,

i am having two simple tables:

# select * from sales;
 client_id | product
-----------+---------
         1 | toolbox
         1 | nails
         2 | nuts

# select * from clients;
 id | name
----+-------
  1 | peter
  2 | john
  3 | marc

now i want to show all client name and the count of the sales in one
table like this:

# select name, count(sales.client_id) from clients, sales where
sales.client_id = clients.id group by name;

 name  | count
-------+-------
 john  |     1
 peter |     2

works fine, but where is marc??? it should look like

 name  | count
-------+-------
 john  |     1
 peter |     2
 marc  |     0

who can i make it work??? i think i know why my select statement
doesnt work, because of the where clause marc will never join this
table because the condition will never be true... but how can i do
it??

i guess its very very simple, but i just cant manage it.

thanks in advance
janning

---------------------------(end of broadcast)---------------------------
TIP 3: if posting/reading through Usenet, please send an appropriate
subscribe-nomail command to majordomo@postgresql.org so that your
message can get through to the mailing list cleanly





В списке pgsql-general по дате отправления:

Предыдущее
От: "Mitch Vincent"
Дата:
Сообщение: Re: showing also value '0' with aggregate count()
Следующее
От: Lincoln Yeoh
Дата:
Сообщение: Re: Encoding passwords