Re: count of occurences PLUS optimisation

Adam, 
try this 
select distinct job_num, count (job_num) from search_record group by job_num ; 
don't worry about an ordered list - group by does it for you. 
Regards, Christoph 
> 
> HACKERS: see the end of this message about a possible optimisation for
> ORDER BY+LIMIT cases (the normal use of LIMIT?)
> 
> Adam wrote:
> > 
> > I help run a job database and have a table of search records.  I want
> > a query that will return the top 10 jobs by search frequency.  I'm
> > familiar with ORDER BY and LIMIT, so I basically need this:
> > 
> > Given a table search_records:
> > job_num
> > -------
> > 1
> > 2
> > 2
> > 3
> > 4
> > 4
> > 4
> > 
> > I want a query that will return:
> > job_num | count
> > --------+------
> > 1       |1
> > 2       |2
> > 3       |1
> > 4       |3
> > 
> > I tried
> > 
> > select distinct job_num, (select count(*) from search_records j where
> > j.job_num=k.job_num) from search_records k
> > 
> > but it is horribly slow (it takes several minutes on a table of about
> > 25k rows!).  I assume it scans the entire table for every job_num in
> > order to count the number of occurences of that job_num, taking order
> > n^2 time.  Since I can easily use job_num as an index (being integers
> > from 0 to roughly 400 so far) I could just do a "select * from
> > search_records" and do the counting in PHP (our HTML pre-processor) in
> > order n time.  However, I don't know how to do an order n*log(n) sort
> > in PHP, just n^2, so there would still be an efficiency problem.
> > I have Postgresql 7.0.3.
> > Help is of course greatly appreciated.
> 
> I have not tried it but how about:-
> 
> select job_num from
> (select job_num, count(*) as c from search_records group by job_num)
> order by c limit 10;
> 
> I am not sure if count(*) would work in this context, if not try count()
> on some field that is in every record. 
> 
> 
> If you can be sure that the top 10 will have at least a certain
> threshold of searches (perhaps >1!) then it MIGHT be faster, due to less
> data being sorted for the outer selects order by, (experiment) to do:-
> 
> select job_num from
> (select job_num, count(*) as c from search_records group by job_num
> HAVING c>1)
> order by c limit 10;
> 
> It would depend on how efficient the ORDER BY and LIMIT work together.
> (The ORDER BY could build a list of LIMIT n items and just replace items
> in that list...a lot more efficient both of memory and comparisons than
> building the full list and then keeping the top n)
> 
> HACKERS: If it does not do this it might be a usefull optimisation. 
> There would probably need to be a cutoff limit on whether to apply this
> method or sort and keep n.  Also for LIMIT plus OFFSET it would need to
> build a list of the the total of the LIMIT and OFFSET figures.
> 
> -- 
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