Re: plperl syntax question
| От | Rob Sargent |
|---|---|
| Тема | Re: plperl syntax question |
| Дата | |
| Msg-id | 1F75920B-15CE-445F-8F2A-B8740DC845D8@gmail.com обсуждение исходный текст |
| Ответ на | plperl syntax question (stan <stanb@panix.com>) |
| Список | pgsql-general |
> On Mar 12, 2020, at 4:34 PM, stan <stanb@panix.com> wrote:
>
> I am trying to run a query in plperl that uses a Perl variable from the
> same function.
>
> Here is the code snippet:
>
> my $stmt = qq("SELECT employee_key from employee where id = '$user' ;");
> elog( NOTICE, "stmt = $stmt" );
> my $rv3 = spi_exec_query('$stmt');
>
> Here is the runtime output:
>
> NOTICE: stmt = "SELECT employee_key from employee where id = 'stan' ;"
> ERROR: syntax error at or near "$" at line 22.
>
> As you can see, the statement seems correctly formatted, right?
>
> What am I doing wrong here?
>
> --
> "They that would give up essential liberty for temporary safety deserve
> neither liberty nor safety."
> -- Benjamin Franklin
>
?try
my $rv3 = spi_exec_query($stmt);
>
>
В списке pgsql-general по дате отправления: