NAN code

I have found a way to assign NAN to a variable, thanks to the library
source code.  Is this better than the code I just posted?  Looks pretty
platform-specific, and we may be better with my earlier code to just use
num, which I have committed to the CURRENT tree.

The strange thing is that isnan(0/0) generates a floating-pointer error
and stops the program, but this does not.  Strange.

---------------------------------------------------------------------------#include <stdio.h>#include <math.h>main(){
double x;    x = 3;        if (isnan((x-x)/(x-x)))        printf("nan\n");    else        printf("not nan\n");}
 

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