BUG #19081: Inconsistent target rows seen by the UPDATE and INSERT statements within the same transaction
От | PG Bug reporting form |
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Тема | BUG #19081: Inconsistent target rows seen by the UPDATE and INSERT statements within the same transaction |
Дата | |
Msg-id | 19081-3745d3e571c420de@postgresql.org обсуждение исходный текст |
Ответы |
Re: BUG #19081: Inconsistent target rows seen by the UPDATE and INSERT statements within the same transaction
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Список | pgsql-bugs |
The following bug has been logged on the website: Bug reference: 19081 Logged by: Ziyu Cui Email address: cuiziyu20@otcaix.iscas.ac.cn PostgreSQL version: 18.0 Operating system: Ubuntu-20.04 Description: At the Repeatable Read isolation level, the target rows seen by UPDATE and INSERT within the same transaction are inconsistent. Steps to reproduce: /* init */ CREATE TABLE t0 (c1 INT PRIMARY KEY, c2 INT); /* init */ INSERT INTO t0 (c1, c2) VALUES (0, 0); -- TRANSACTION 1; BEGIN; UPDATE t0 SET c1 = 5, c2 = 5 WHERE c2 = 0; COMMIT; -- TRANSACTION 2; BEGIN; INSERT INTO t0 (c1, c2) VALUES (2, 2); INSERT INTO t0 (c1, c2) VALUES (0, 12); UPDATE t0 SET c1 = 9, c2 = 9 WHERE c2 = 5; COMMIT; -- Submit Order /* T1 */ BEGIN; /* T1 */ UPDATE t0 SET c1 = 5, c2 = 5 WHERE c2 = 0; /* T2 */ BEGIN; /* T2 */ INSERT INTO t0 (c1, c2) VALUES (2, 2); /* T1 */ COMMIT; /* T2 */ INSERT INTO t0 (c1, c2) VALUES (0, 12); /* T2 */ UPDATE t0 SET c1 = 9, c2 = 9 WHERE c2 = 5; /* T2 */ COMMIT; SELECT * FROM t0; c1 | c2 ----+---- 5 | 5 2 | 2 0 | 12 After transaction 1 was committed, the second INSERT in transaction 2 successfully inserted the value (0, 12) because transaction 1 had updated the row (0, 0). However, the UPDATE in transaction 2 did not update the row (5, 5) that were updated in transaction 1. The final database result seems to indicate that the second INSERT in transaction 2 can see the update made by transaction 1, but the UPDATE in transaction 2 cannot see the update made by transaction 1. Why do these two statements show different effects when exposed to the influence of transaction 1? Another case: /* init */ CREATE TABLE t0 (c1 INT PRIMARY KEY, c2 INT); /* init */ INSERT INTO t0 (c1, c2) VALUES (0, 0); -- TRANSACTION 1; BEGIN; UPDATE t0 SET c1 = 5, c2 = 5 WHERE c2 = 0; COMMIT; -- TRANSACTION 2; BEGIN; INSERT INTO t0 (c1, c2) VALUES (2, 2); INSERT INTO t0 (c1, c2) VALUES (6, 12); UPDATE t0 SET c1 = 9, c2 = 9 WHERE c2 = 0; COMMIT; -- Submit Order /* T1 */ BEGIN; /* T1 */ UPDATE t0 SET c1 = 5, c2 = 5 WHERE c2 = 0; /* T2 */ BEGIN; /* T2 */ INSERT INTO t0 (c1, c2) VALUES (2, 2); /* T1 */ COMMIT; /* T2 */ INSERT INTO t0 (c1, c2) VALUES (6, 12); /* T2 */ UPDATE t0 SET c1 = 9, c2 = 9 WHERE c2 = 0; -- ERROR: could not serialize access due to concurrent update /* T2 */ COMMIT; SELECT * FROM t0; c1 | c2 ----+---- 5 | 5 Although transaction 1 has been committed, the UPDATE in transaction 2 still conflicts with transaction 1 and reports an error "could not serialize access due to concurrent update". Why was transaction 2 affected by the UPDATE in transaction 1 at this time?
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