Hi,
Thanks for the reply.
I have done it in this way:
[code]
FOR vDISTRITOS_NA_TABELA IN
SELECT array[id_distrito] FROM am_newsletter_distritos
WHERE email = pEMAIL and id_website_recolha = pID_WEBSITE_RECOLHA
LOOP
vDISTRITOS_NA_TABELA_CONST := vDISTRITOS_NA_TABELA_CONST || vDISTRITOS_NA_TABELA;
END LOOP;
[/code]
Best Regards,
On Sun, Feb 21, 2010 at 3:25 PM, Andreas Kretschmer
<akretschmer@spamfence.net> wrote:
> One more time, thanks for the reply. I'am using postgre 8.3. I think I don't
> have the array_agg(), there is another way of doing it?
Sure.
The doc contains an example for a user-defined aggregate-function:
http://www.postgresql.org/docs/8.4/interactive/xaggr.html
It works with versions prior 8.4.
test=*# CREATE AGGREGATE array_accum (anyelement)
test-# (
test(# sfunc = array_append,
test(# stype = anyarray,
test(# initcond = '{}'
test(# );
CREATE AGGREGATE
Zeit: 44,645 ms
test=*# select array_accum(a) from foo;
array_accum
-------------
{1,3,5,7}
(1 Zeile)
Andreas
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