Re: how to do this query

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От msi77
Тема Re: how to do this query
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Msg-id 18301263077520@webmail108.yandex.ru
обсуждение исходный текст
Ответ на how to do this query  (Wes James <comptekki@gmail.com>)
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> schols_seleced like '%' || short_name || '%' doesn't make sense to me

select 'Ya-Ya' from 
(select
'schol1:schol2:schol3' as schols_selects 
) AS X
where schols_selects like '%schol2%'

> If you look at the contents of these fields short name containts
> "schol1", schols_selects containts "schol1:schol2:schol3" so
> schols_seleced like '%' || short_name || '%' doesn't make sense to me
> since the like operator is trying to find text1 in text two with %%
> right?
> 2010/1/9 msi77 <msi77@yandex.ru>:
> > Развернуть 
> > How about
> > 
> > schols_selected like '%' || short_name || '%'
> > > Развернуть 
> > > I have two tables:
> > > students
> > > stu_name
> > > schols_selected
> > > scholarships
> > > schol_name
> > > short_name
> > > schols_selected is made up of scholarships the students have selected,
> > > the field content will look like schol1:schol2:schol3
> > > I need a select that does something like this
> > > select schol_name, short_name, stu_name, schols_selected
> > > from scholarships, students
> > > where short_name is in schols_selected
> > > I have tried:
> > > where short_name like '%' || schols_selected || '%'
> > > but i'm not sure how to include a field result in between like operators.
> > > how do I get a list of scholarships based one which student selected
> > > it where the selected result is a string of colon seperated options?
> > > thx,
> > > -wj
> > > --
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> 

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