Re: Allow round() function to accept float and double precision

David Rowley <dgrowleyml@gmail.com> writes:
> I don't really agree that it will work fine in all cases though. If
> the numeric has more than 1000 digits left of the decimal point then
> the method won't work at all.

But what we're talking about is starting from a float4 or float8
input, so it can't be more than ~308 digits.

            regards, tom lane