Re: remove indexes on a column?
| От | Tom Lane | 
|---|---|
| Тема | Re: remove indexes on a column? | 
| Дата | |
| Msg-id | 15591.1221020616@sss.pgh.pa.us обсуждение исходный текст | 
| Ответ на | remove indexes on a column? ("Vance Maverick" <vmaverick@pgp.com>) | 
| Ответы | Re: remove indexes on a column? | 
| Список | pgsql-general | 
"Vance Maverick" <vmaverick@pgp.com> writes:
> I'd like to write a SQL script, possibly with some PL/pgSQL, that can
> find all indexes on a column -- so I can remove them, and set up
> exactly the indexes I want.
Yeah, this seems a bit tricky if you have expression indexes involving
the column.  I concur that trying to parse the expressions is a bad
idea --- even if your code works today, it'll probably break in future
PG releases, because the nodetree representation is not very stable.
What I'd look for is pg_depend entries showing indexes that depend on
the column.  Here's a hint:
regression=# create table foo (f1 int);
CREATE TABLE
regression=# create index fooi on foo (abs(f1));
CREATE INDEX
regression=# select * from pg_depend where refobjid = 'foo'::regclass;
 classid | objid  | objsubid | refclassid | refobjid | refobjsubid | deptype
---------+--------+----------+------------+----------+-------------+---------
    1247 | 534605 |        0 |       1259 |   534603 |           0 | i
    1259 | 534606 |        0 |       1259 |   534603 |           1 | a
(2 rows)
regression=# select 534606::regclass;
 regclass
----------
 fooi
(1 row)
            regards, tom lane
		
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