Problems with group by ... order by
| От | John D. Burger |
|---|---|
| Тема | Problems with group by ... order by |
| Дата | |
| Msg-id | 1307c6f5709cab391e87d78e6744f605@mitre.org обсуждение |
| Ответы |
Re: Problems with group by ... order by
Re: Problems with group by ... order by |
| Список | pgsql-general |
I can't figure out why the following doesn't work:
select
(case
when count1 < 300 then 'Other'
else country1
end) as country2,
sum(count1) as count2
from (select coalesce(country, 'None') as country1, count(*) as count1
from userProfiles group by country1) as counts1
group by country2
order by (country2 = 'Other'), count2 desc
Basically, I want to get an aggregate count of users across countries
(including the "None" country), then I want to aggregate those
countries with counts less than 300 into an Other pseudo-country. I
want it sorted by this final count, except I want the Other entry to be
last. This works fine if I leave out the first order-by condition -
the result is sorted by the final count. But with the query as written
above, I get:
ERROR: column "country2" does not exist
It also works fine if I just order by country2, count2 - it seems to be
the comparison that's the problem. And ordering by a boolean after
aggregating works fine in this simpler case:
select country, count(*) as cnt
from userProfiles
group by country
order by country is null, cnt;
This puts the NULL count at the end.
This is with PG 7.4.7. Any advice appreciated, including how to do
this in a simpler fashion.
- John Burger
MITRE
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