Re: how to found a variable is in a aggregation or not?

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От Yi Zhao
Тема Re: how to found a variable is in a aggregation or not?
Дата
Msg-id 1216128716.12728.0.camel@localhost.localdomain
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Ответ на Re: how to found a variable is in a aggregation or not?  ("Pavel Stehule" <pavel.stehule@gmail.com>)
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it's works,
thanks a lot!

regards,
Yi
On Tue, 2008-07-15 at 13:30 +0200, Pavel Stehule wrote:
> Hello
>
> in this case you must not use quoting
>
> postgres=# create or replace function anytest(val text) returns boolean as $$
> begin
>        perform 1 where val in ('hello', 'world', 'test');
>        if not found then
>                return false;
>        else
>                return true;
>        end if;
> end;
> $$ language plpgsql;
> CREATE FUNCTION
> Time: 3,342 ms
> postgres=# select anytest('hello');
>  anytest
> ---------
>  t
> (1 row)
>
> Time: 42,034 ms
> postgres=# select anytest('helloa');
>  anytest
> ---------
>  f
> (1 row)
>
> Time: 0,468 ms
> postgres=#
>
> you have to use quoting only together dynamic sql, etc EXECUTE statement
>
> regards
> Pavel Stehule
>
> 2008/7/15 Yi Zhao <yi.zhao@alibaba-inc.com>:
> > I want to check a variable is in a aggregattion or not, so I create a
> > function as below:
> >
> > create or replace function anytest(val text) returns boolean as $$
> > begin
> >        perform 1 where quote_literal(val) in ('hello', 'world', 'test');
> >        if not found then
> >                return false;
> >        else
> >                return true;
> >        end if;
> > end;
> > $$ language plpgsql;
> >
> > but when I used, I got the result below, why?
> >
> > test=# select anytest('world111');
> >  anytest
> > ---------
> >  f
> > (1 row)
> >
> > test=# select anytest('world');
> >  anytest
> > ---------
> >  f
> > (1 row)
> >
> >
> > any help is appreciated.
> >
> > regards,
> > Zy
> >
> >
> > --
> > Sent via pgsql-general mailing list (pgsql-general@postgresql.org)
> > To make changes to your subscription:
> > http://www.postgresql.org/mailpref/pgsql-general
> >
>


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